Tokyo, July 25 (MNN) India’s star shuttler PV Sindhu comfortably won against Israeli Polikarpova Ksenia in the opening round to begin her hunt for a gold in the women’s singles at the Tokyo Olympics on Sunday.
Sindhu beat Ksenia in straight games 21-7, 21-10 in their first Group J match on the second day of the Games. Sindhu will next take on Hong Kong’s Cheung Ngan Yi on or before July 28, as the exact match date is yet to be determined.
A reigning world champion, Sindhu lost first two points in her match but soon got into the groove, employing frequent cross-court shots to accumulate winners.
The Indian badminton star won 13 points in a row at one point to surge into a big lead. Sindhu dropped two points while leading 19-5 but closed out the first game in a little over 13 minutes.
Polikarpova was not helped by her frequent errors and PV Sindhu wrapped up the victory in just 29 minutes.
Sindhu had won a silver at Rio 2016 and is expected to win another medal for the country.
Sindhu is the first Indian woman to become a badminton world champion, having won the World Badminton Championship in 2019. She also has a BWF World Tour title in her bag and has finished runner-up on four occasions.
Sindhu has been working under the tutelage of South Korean coach Park Tae-sang, who won the bronze medal at the 2004 Asian Games. Tae-sang has been coaching Sindhu since September 2019.
Sindhu is placed in Group J, alongside Hong Kong’s Cheung Ngan Yi, who is world number 34, and Israel’s Ksenia Polikarpova. Interestingly, she has a 100 per cent win record against the duo.
There is a possibility that Sindhu might face Akane Yamaguchi of Japan in the quarterfinals should she progress from the group stages.
Although Sindhu defeated Yamaguchi earlier this year at the All England Open, the Japanese star notably beat the Indian in the BWF World Tour final in December 2019.